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On an only-inplace-colors response, we can deduce which colors are in place

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Matúš Púll 2024-11-04 15:22:33 +01:00
parent f0fda2b9c9
commit fed923923b
1 changed files with 28 additions and 3 deletions
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31
solver.hpp
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@ -61,6 +61,14 @@ public:
known.empty_color(col);
}
}
void here(vector<int> guess) {
for(int n = 0; n < known.N; n++)
if(guess[n] > -1)
for(int col = 0; col < known.M; col++) {
if(col != guess[n])
known.possible[n][col] = 0;
}
}
void not_here(vector<int> guess) {
for(int n = 0; n < known.N; n++)
if(guess[n] > -1)
@ -80,6 +88,12 @@ public:
vector<int> guess = cleaned.guess;
vector<int> response = cleaned.response;
// Get number of colors, that can be on their positions
int possible_count = 0;
for(int n = 0; n < known.N; n++)
if(known.possible[n][guess[n]])
possible_count++;
// None of these colors are there
if(response[0] == 0 && response[1] == 0) {
empty(guess);
@ -91,11 +105,22 @@ public:
not_here(guess);
// At least only on the right spot
else if(response[0] == 0)
if_not_here_then_nowhere(guess);
else if(response[0] == 0) {
// Only colors that can be on these positions are left
if(response[1] == possible_count) {
here(guess);
something_to_learn = false;
}
else
if_not_here_then_nowhere(guess);
}
// Nonzero / nonzero
else {}
else {
// Only colors that can be on these positions are left
if(response[1] == possible_count)
here(guess);
}
return something_to_learn;
}